Question: evaluate 2log 12-3log6+2log24.
The expression is
E = 2log(12) - 3log(6) + 2log(24)
using n.log(x) = log(x^n),
E = log(12^2) + log(24^2) - log(6^3)
E = log([288^2]/6^3)
E = log(82,944/216)
E = log(384)
E = 2.5844 (taken to the base 10 - not natural logs)